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Author Topic: thinning Tom's  (Read 3808 times)

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Offline SwampDonkey

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Re: thinning Tom's
« Reply #40 on: December 11, 2008, 11:44:29 am »
Actually Tom, you have to look at it from the stand point of the tree.  I get tripped up with that sometimes.

43560 ft2 x tree + 43560 ft2 x tree = 272 trees/acre
  240 ft2 x acre      120 ft2 x acre 
                          2

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Pre-commercial thinning pays off. :)
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Offline SwampDonkey

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Re: thinning Tom's
« Reply #41 on: December 11, 2008, 12:19:05 pm »
If you work it out on a grid like this, we'll call option # 2

     12               24                12                24                 12
o            o                        o            o                        o            o

                                                                                                  10

o            o                        o            o                        o            o

                                                                                                   10

o            o                        o            o                        o            o

                                                                                                   10

o            o                        o            o                        o            o

                                                                                                   10

o            o                        o            o                        o            o

                                                                                                    10

o            o                        o            o                        o            o

That's an area of 84 feet x 50 feet, with 36 trees, represents 4200 ft2

43560 ft2/acre x 36 trees   = 373 trees/acre   take your pick :D
    4200 ft2

Only trouble is it doesn't hold up if you use different sized sample plots. :D
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Offline Tom

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Re: thinning Tom's
« Reply #42 on: December 11, 2008, 02:02:11 pm »
I don't know what is right, but I like the 372 trees per acre better than the 272 when I stuff my wallet.  :D
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Offline SwampDonkey

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Re: thinning Tom's
« Reply #43 on: December 11, 2008, 03:12:36 pm »
Yeah I know that train of thought is what I like too. :D Since the spacing is not uniform, but there is a pattern I'm sure there is still a mathematical way to compute it. It's a lot easier to calculate when the spacing is uniform that is for sure. :D
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Offline isawlogs

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Re: thinning Tom's
« Reply #44 on: December 12, 2008, 02:29:51 pm »
Try using 10 on one side and 18 on the other .
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Offline SwampDonkey

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Re: thinning Tom's
« Reply #45 on: December 12, 2008, 03:18:01 pm »
Yes, I did that also, here was the result.

242  trees/acre :-\


It's probably some crazy quadratic math :-X
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Offline Tom

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Re: thinning Tom's
« Reply #46 on: December 12, 2008, 03:35:05 pm »
I don't like that one as much.  :-\

Maybe if you were to hold a prism up at arms length and count the empy spaces, or sumthin'.
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Offline SwampDonkey

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Re: thinning Tom's
« Reply #47 on: December 12, 2008, 04:22:04 pm »
It's perplexing. :D


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Online WDH

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Re: thinning Tom's
« Reply #48 on: December 12, 2008, 09:56:05 pm »
I guess that I am going to have to come down there and cruise it :).
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Offline Jeff

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Re: thinning Tom's
« Reply #49 on: December 12, 2008, 10:48:00 pm »
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Offline nsmike

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Re: thinning Tom's
« Reply #50 on: December 13, 2008, 12:17:51 am »
I used the formula for 12 ft between rows and 10 ft between trees for 363 trees per acre if reduce it by 1/3  for the missing rows you get 242 trees per acre. I suspect that you would have one additional outside row which  you could add in if you know its length/10 but it would only apply to the outside row.
Mike
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Offline SwampDonkey

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Re: thinning Tom's
« Reply #51 on: December 13, 2008, 07:03:32 am »
I think Marcel's and nsmike's is the only way you can compute it, because you can't get more than 363 trees in an acre at 12 x 10 foot spacing, and there is 1/3 less....

so 242 trees/acre


The way I computed it a while back was this.....

43560 ft2/acre        = 242 trees/acre
(12+6 ft) x (5 + 5 ft)
            tree

It just seems so low. Too bad Tom, I tried to get you more trees. ;D
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Offline Ron Scott

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Re: thinning Tom's
« Reply #52 on: December 13, 2008, 09:50:25 am »
Why not just do a 100% tree count and then you will know with some accuracy. ;)
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Offline SwampDonkey

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Re: thinning Tom's
« Reply #53 on: December 13, 2008, 05:52:17 pm »
For sure, eh? :D

I know when we do sample plots we always think in terms of crown space of the trees being spaced or planted and how many of those growing spaces can we fit inside a sample plot and ultimately how many in  a unit of area, hectares or acres. I know that a ha is 10000 m2 and we use a sample plot size of 40 m2, which is 1/250th of a ha. If I have an average of 8 in my plot I have 2000 trees/ha, if I have 10 I have 2500 trees/ha. 2500 or 2m x 2m or (6.5 feet apart) is the ultimate spacing when thinning and planting softwood. 1.82m (6 foot) for hardwood or 3000 trees/ha.
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Pre-commercial thinning pays off. :)
'If she wants to play lumberjack, she's going to have to learn to handle her end of the log.'
Dirty Harry

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Re: thinning Tom's
« Reply #54 on: December 13, 2008, 08:50:25 pm »
242 trees per acre is a gracious plenty for slash.  Too dense and they will stagnate.  They are much more persnickity than loblolly.
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Offline semologger

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Re: thinning Tom's
« Reply #55 on: December 13, 2008, 09:16:43 pm »
I am just takeing 10th acre plots. I stand in the row i just took out and make a circle. 37 feet to the outside ring. I just count my trees in the circle so i know my basel area. I have my eye down now on thinning so i am not takeing many plots. I need to take out every other tree in each row. So if i have a row missing alot of trees I will leave a few heavy on the other row. That way i can keep my trees per acre up.
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